If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12m^2+5m-4=0
a = 12; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·12·(-4)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{217}}{2*12}=\frac{-5-\sqrt{217}}{24} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{217}}{2*12}=\frac{-5+\sqrt{217}}{24} $
| 21-b=11b= | | 57+(3x+7)=x | | -4-p=-2P= | | 5m^2+5m-4=0 | | .p-11=-5 | | 9-4g=-15g= | | .p-11=55 | | 0x3=72 | | 6p^2+23p-279=0 | | -3b+2=4b+ | | –u+92=1 | | 6y+12+6y=12 | | -9v+6=-10v | | 2/9x-4=2/3x= | | 57+r=67 | | 2x=42/5 | | -2y+17=-13y= | | 3n+7=28n= | | 4x^2+14x-79=0 | | 7(x+6+7x=9 | | 5c-24=-4c= | | 11x-7x+12=2x+3-21 | | t÷5-7=15 | | 9n+4=5n+18n= | | 12y+12=12 | | 8t+1=3t-19t= | | 5.3x-14.6=22.5 | | a÷6+8=6 | | 5(2z−10)=-10 | | 213=28-u | | 4^3x=2^x+1 | | 5+3=2b+3 |